x^2-10x+25=3x-3

Solution for x^2-10x+25=3x-3 equation:

x^2-10x+25=3x-3

We move all terms to the left:

x^2-10x+25-(3x-3)=0

We get rid of parentheses

x^2-10x-3x+3+25=0

We add all the numbers together, and all the variables

x^2-13x+28=0

a = 1; b = -13; c = +28;
Δ = b2-4ac
Δ = -132-4·1·28
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{57}}{2*1}=\frac{13-\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{57}}{2*1}=\frac{13+\sqrt{57}}{2}
$